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-50x^2=-50
We move all terms to the left:
-50x^2-(-50)=0
We add all the numbers together, and all the variables
-50x^2+50=0
a = -50; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-50)·50
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*-50}=\frac{-100}{-100} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*-50}=\frac{100}{-100} =-1 $
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